SQL中自己创建函数 分割字符串

网络整理 - 07-27

以下为引用的内容:
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[getEPnum]') and xtype in (N'FN', N'IF', N'TF'))

  drop function [dbo].[getEPnum]


  GO

  if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[getstrcount]') and xtype in (N'FN', N'IF', N'TF'))

  drop function [dbo].[getstrcount]

  GO

  if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[getstrofindex]') and xtype in (N'FN', N'IF', N'TF'))

  drop function [dbo].[getstrofindex]

  GO

  SET QUOTED_IDENTIFIER ON

  GO

  SET ANSI_NULLS ON

  GO

  --- 这个函数直接调用了另外的两个函数,可以先阅读下面提到的两个函数

  CREATE  function getEPnum (@str varchar(8000))

  returns varchar(8000)

  as

  begin

  declare @str_return varchar(8000) 

  declare @i int

  declare @temp_i int

  declare @onlineornot int

  declare @findepnumok int

  -- 用来取得一个epnum,

  -- 规则:首先从chatid中取,如果有在线得,则取得最前面得在线得返回

  --    如果全部不在线,则返回 ‘00000000’

   select @findepnumok = 0

  select @temp_i = 0

  IF len(@str)<=0

  begin

  SELECT @str_return = '00000000'

  end

  else

  begin

  select @i = dbo.getstrcount(@str,',')
以下为引用的内容:
 WHILE @temp_i<@i

  BEGIN

  select @onlineornot = online from wwchat_user where epnum=dbo.getstrofindex(@str,',',@temp_i)      

  IF (@onlineornot=1)

  begin

  select @str_return =dbo.getstrofindex(@str,',',@temp_i)

  select @findepnumok = 1 --找到epnum后置为1

  BREAK

  end

  ELSE

  begin

  select @temp_i = @temp_i + 1

  select @findepnumok = 0 --找不到epnum后置为1

  end

  END

  if @findepnumok = 0

  begin

  SELECT @str_return = '00000000'

  end

  end

  return @str_return 

  end

  GO

  SET QUOTED_IDENTIFIER OFF

  GO

  SET ANSI_NULLS ON

  GO

  SET QUOTED_IDENTIFIER ON

  GO

  SET ANSI_NULLS ON

  GO

  --getstrcount 输入一个没有分割的字符串,以及分割符

  --返回数组的个数

  CREATE   function getstrcount (@str varchar(8000),@splitstr varchar(100)) 

  --returns varchar(8000) 

  returns int

  as 

  begin 

  declare @int_return int 

  declare @start int 

  declare @next int

   declare @location int 

  select @next = 0

  select @location = 1

   if len(@str)<len(@splitstr)

  select @int_return =0

  if charindex(@splitstr,@str) = 0

  select @int_return =0

   while (@location<>0) 

  begin 

  select @start = @location + 1
以下为引用的内容: