Ajax联动下拉框的实现例子

网络整理 - 07-26

这是采用ajax技术,刷新是肯定的,是在我们察觉不到的速度完成.XMLHTTP牺牲页面的方法,我们之所以看不见刷新,是因为所有的工作都是在牺牲页面上进行的,里面"翻江倒海"的"折腾",我们看不见,效率上差些!

AjaxPro.dll 下载地址 

Web.Config
<?xml version="1.0"?>
<configuration>
 <system.web>
      <httpHandlers>
   <add verb="POST,GET" path="ajax/*.ashx" type="Ajax.PageHandlerFactory, Ajax" />
   <add verb="POST,GET" path="ajaxpro/*.ashx" type="AjaxPro.AjaxHandlerFactory,AjaxPro.2"/>
  </httpHandlers>
 </system.web>
</configuration>

AjaxTest.aspx

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="AjaxTest.aspx.cs" Inherits="AjaxTest" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "">

<html xmlns="" >
<head runat="server">
    <title>无标题页</title>

</head>

<body>
<script language="javascript" type="text/javascript">
function areaResult()
{
var area=document.getElementById("DropDownList1");
//alert(area.value);
AjaxTest.GetCityList(area.value,get_city_Result_CallBack);
}
function get_city_Result_CallBack(response)
{
if (response.value != null)
{
  document.all("DropDownList2").length=0;    
  var ds = response.value;
  if(ds != null && typeof(ds) == "object" && ds.Tables != null)
  {
   for(var i=0; i<ds.Tables[0].Rows.length; i++)
  {
   var name=ds.Tables[0].Rows[i].name;
   var id=ds.Tables[0].Rows[i].id;
   document.all("DropDownList2").options.add(new Option(name,id));
  }
  //document.all("TextBox1").value="";  
 }
}
return
}

</script>
  <form id="form1" runat="server">
        
 <asp:DropDownList ID="DropDownList1" runat="server">
        </asp:DropDownList>
        <asp:DropDownList ID="DropDownList2" runat="server">
        </asp:DropDownList> 
      <br />
    </form>
</body>
</html>

AjaxTest.cs

using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using MeetWeb;
public partial class AjaxTest : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
       AjaxPro.Utility.RegisterTypeForAjax(typeof(AjaxTest));
       if (!Page.IsPostBack)
       {
           BindData();

       }
    }
    private void BindData()
    {
        DataSet ds = new DataSet();
          String sql = "Select id,name from test";
          try
          {
              ds = GetDataSet(sql, "test");
              this.DropDownList1.DataSource = ds.Tables[0];
              this.DropDownList1.DataTextField = "name";
              this.DropDownList1.DataValueField = "id";
              this.DropDownList1.DataBind();